c碼游戲小說
❶ 求C語言小游戲源程序
我的樓主可以自己玩一下
試試吧
#define N 200
#include <graphics.h>
#include <stdlib.h>
#include <dos.h>
#define LEFT 0x4b00
#define RIGHT 0x4d00
#define DOWN 0x5000
#define UP 0x4800
#define ESC 0x011b
int i,key;
int score=0;/*得分*/
int gamespeed=50000;/*游戲速度自己調整*/
struct Food
{
int x;/*食物的橫坐標*/
int y;/*食物的縱坐標*/
int yes;/*判斷是否要出現食物的變數*/
}food;/*食物的結構體*/
struct Snake
{
int x[N];
int y[N];
int node;/*蛇的節數*/
int direction;/*蛇移動方向*/
int life;/* 蛇的生命,0活著,1死亡*/
}snake;
void Init(void);/*圖形驅動*/
void Close(void);/*圖形結束*/
void DrawK(void);/*開始畫面*/
void GameOver(void);/*結束游戲*/
void GamePlay(void);/*玩游戲具體過程*/
void PrScore(void);/*輸出成績*/
/*主函數*/
void main(void)
{
Init();/*圖形驅動*/
DrawK();/*開始畫面*/
GamePlay();/*玩游戲具體過程*/
Close();/*圖形結束*/
}
/*圖形驅動*/
void Init(void)
{
int gd=DETECT,gm;
initgraph(&gd,&gm,"c:\\tc");
cleardevice();
}
/*開始畫面，左上角坐標為（50，40），右下角坐標為（610，460）的圍牆*/
void DrawK(void)
{
/*setbkcolor(LIGHTGREEN);*/
setcolor(11);
setlinestyle(SOLID_LINE,0,THICK_WIDTH);/*設置線型*/
for(i=50;i<=600;i+=10)/*畫圍牆*/
{
rectangle(i,40,i+10,49); /*上邊*/
rectangle(i,451,i+10,460);/*下邊*/
}
for(i=40;i<=450;i+=10)
{
rectangle(50,i,59,i+10); /*左邊*/
rectangle(601,i,610,i+10);/*右邊*/
}
}
/*玩游戲具體過程*/
void GamePlay(void)
{
randomize();/*隨機數發生器*/
food.yes=1;/*1表示需要出現新食物,0表示已經存在食物*/
snake.life=0;/*活著*/
snake.direction=1;/*方嚮往右*/
snake.x[0]=100;snake.y[0]=100;/*蛇頭*/
snake.x[1]=110;snake.y[1]=100;
snake.node=2;/*節數*/
PrScore();/*輸出得分*/
while(1)/*可以重復玩游戲,壓ESC鍵結束*/
{
while(!kbhit())/*在沒有按鍵的情況下,蛇自己移動身體*/
{
if(food.yes==1)/*需要出現新食物*/
{
food.x=rand()%400+60;
food.y=rand()%350+60;
while(food.x%10!=0)/*食物隨機出現後必須讓食物能夠在整格內,這樣才可以讓蛇吃到*/
food.x++;
while(food.y%10!=0)
food.y++;
food.yes=0;/*畫面上有食物了*/
}
if(food.yes==0)/*畫面上有食物了就要顯示*/
{
setcolor(GREEN);
rectangle(food.x,food.y,food.x+10,food.y-10);
}
for(i=snake.node-1;i>0;i--)/*蛇的每個環節往前移動,也就是貪吃蛇的關鍵演算法*/
{
snake.x[i]=snake.x[i-1];
snake.y[i]=snake.y[i-1];
}
/*1,2,3,4表示右,左,上,下四個方向,通過這個判斷來移動蛇頭*/
switch(snake.direction)
{
case 1:snake.x[0]+=10;break;
case 2: snake.x[0]-=10;break;
case 3: snake.y[0]-=10;break;
case 4: snake.y[0]+=10;break;
}
for(i=3;i<snake.node;i++)/*從蛇的第四節開始判斷是否撞到自己了，因為蛇頭為兩節，第三節不可能拐過來*/
{
if(snake.x[i]==snake.x[0]&&snake.y[i]==snake.y[0])
{
GameOver();/*顯示失敗*/
snake.life=1;
break;
}
}
if(snake.x[0]<55||snake.x[0]>595||snake.y[0]<55||
snake.y[0]>455)/*蛇是否撞到牆壁*/
{
GameOver();/*本次游戲結束*/
snake.life=1; /*蛇死*/
}
if(snake.life==1)/*以上兩種判斷以後,如果蛇死就跳出內循環，重新開始*/
break;
if(snake.x[0]==food.x&&snake.y[0]==food.y)/*吃到食物以後*/
{
setcolor(0);/*把畫面上的食物東西去掉*/
rectangle(food.x,food.y,food.x+10,food.y-10);
snake.x[snake.node]=-20;snake.y[snake.node]=-20;
/*新的一節先放在看不見的位置,下次循環就取前一節的位置*/
snake.node++;/*蛇的身體長一節*/
food.yes=1;/*畫面上需要出現新的食物*/
score+=10;
PrScore();/*輸出新得分*/
}
setcolor(4);/*畫出蛇*/
for(i=0;i<snake.node;i++)
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,
snake.y[i]-10);
delay(gamespeed);
setcolor(0);/*用黑色去除蛇的的最後一節*/
rectangle(snake.x[snake.node-1],snake.y[snake.node-1],
snake.x[snake.node-1]+10,snake.y[snake.node-1]-10);
} /*endwhile（！kbhit）*/
if(snake.life==1)/*如果蛇死就跳出循環*/
break;
key=bioskey(0);/*接收按鍵*/
if(key==ESC)/*按ESC鍵退出*/
break;
else
if(key==UP&&snake.direction!=4)
/*判斷是否往相反的方向移動*/
snake.direction=3;
else
if(key==RIGHT&&snake.direction!=2)
snake.direction=1;
else
if(key==LEFT&&snake.direction!=1)
snake.direction=2;
else
if(key==DOWN&&snake.direction!=3)
snake.direction=4;
}/*endwhile(1)*/
}
/*游戲結束*/
void GameOver(void)
{
cleardevice();
PrScore();
setcolor(RED);
settextstyle(0,0,4);
outtextxy(200,200,"GAME OVER");
getch();
}
/*輸出成績*/
void PrScore(void)
{
char str[10];
setfillstyle(SOLID_FILL,YELLOW);
bar(50,15,220,35);
setcolor(6);
settextstyle(0,0,2);
sprintf(str,"score:%d",score);
outtextxy(55,20,str);
}
/*圖形結束*/
void Close(void)
{
getch();
closegraph();
}
❷ 有沒有類似末世魔神遊戲那樣的末世小說，基地類的或是重生的末世小說，西方玄幻的也行，最好200W字以上。
極限恐懼 亡者系統 望採納
❸ 求幾C語言個小游戲代碼，簡單的，要注釋、、謝謝了、
// Calcu24.cpp : Defines the entry point for the console application.
//
/*
6-6
24點游戲
*/
#include "conio.h"
#include "stdlib.h"
#include "time.h"
#include "math.h"
#include "string.h"/*
從一副撲克牌中，任取4張。
2-10 按其點數計算(為了表示方便10用T表示)，J,Q,K,A 統一按 1 計算
要求通過加減乘除四則運算得到數字 24。
本程序可以隨機抽取紙牌，並用試探法求解。
*/void GivePuzzle(char* buf)
{
char card[] = {'A','2','3','4','5','6','7','8','9','T','J','Q','K'}; for(int i=0; i<4; i++){
buf[i] = card[rand() % 13];
}
}
void shuffle(char * buf)
{
for(int i=0; i<5; i++){
int k = rand() % 4;
char t = buf[k];
buf[k] = buf[0];
buf[0] = t;
}
}
int GetCardValue(int c)
{
if(c=='T') return 10;
if(c>='0' && c<='9') return c - '0';
return 1;
}
char GetOper(int n)
{
switch(n)
{
case 0:
return '+';
case 1:
return '-';
case 2:
return '*';
case 3:
return '/';
} return ' ';
}double MyCalcu(double op1, double op2, int oper)
{
switch(oper)
{
case 0:
return op1 + op2;
case 1:
return op1 - op2;
case 2:
return op1 * op2;
case 3:
if(fabs(op2)>0.0001)
return op1 / op2;
else
return 100000;
} return 0;
}
void MakeAnswer(char* answer, int type, char* question, int* oper)
{
char p[4][3];
for(int i=0; i<4; i++)
{
if( question[i] == 'T' )
strcpy(p[i], "10");
else
sprintf(p[i], "%c", question[i]);
}
switch(type)
{
case 0:
sprintf(answer, "%s %c (%s %c (%s %c %s))",
p[0], GetOper(oper[0]), p[1], GetOper(oper[1]), p[2], GetOper(oper[2]), p[3]);
break;
case 1:
sprintf(answer, "%s %c ((%s %c %s) %c %s)",
p[0], GetOper(oper[0]), p[1], GetOper(oper[1]), p[2], GetOper(oper[2]), p[3]);
break;
case 2:
sprintf(answer, "(%s %c %s) %c (%s %c %s)",
p[0], GetOper(oper[0]), p[1], GetOper(oper[1]), p[2], GetOper(oper[2]), p[3]);
break;
case 3:
sprintf(answer, "((%s %c %s) %c %s) %c %s",
p[0], GetOper(oper[0]), p[1], GetOper(oper[1]), p[2], GetOper(oper[2]), p[3]);
break;
case 4:
sprintf(answer, "(%s %c (%s %c %s)) %c %s",
p[0], GetOper(oper[0]), p[1], GetOper(oper[1]), p[2], GetOper(oper[2]), p[3]);
break;
}
}
bool TestResolve(char* question, int* oper, char* answer)
{
// 等待考生完成
int type[5]={0,1,2,3,4};//計算類型
double p[4];
double sum=0;
//
for(int i=0; i<4; i++) //循環取得點數
{
p[i]=GetCardValue(int(question[i]));
} for(i=0;i<5;i++)
{
MakeAnswer(answer,type[i],question,oper); //獲取可能的答案
switch(type[i])
{
case 0:
sum=MyCalcu(p[0],MyCalcu( p[1],MyCalcu(p[2], p[3], oper[2]),oper[1]),oper[0]); //A*(B*(c*D))
break;
case 1:
sum=MyCalcu(p[0],MyCalcu(MyCalcu(p[1], p[2], oper[1]),p[3],oper[2]),oper[0]); //A*((B*C)*D)
break;
case 2:
sum=MyCalcu(MyCalcu(p[0], p[1], oper[0]),MyCalcu(p[2], p[3], oper[2]),oper[1]); // (A*B)*(C*D)
break;
case 3:
sum=MyCalcu(MyCalcu(MyCalcu(p[0], p[1], oper[0]),p[2],oper[1]),p[3],oper[2]); //((A*B)*C)*D
break;
case 4:
sum=MyCalcu(MyCalcu(p[0],MyCalcu(p[1], p[2], oper[1]),oper[0]),p[3],oper[2]); //(A*(B*C))*D
break;
}
if(sum==24) return true;
}
return false;
}
/*
採用隨機試探法：就是通過隨機數字產生 加減乘除的 組合，通過大量的測試來命中的解法
提示：
1. 需要考慮用括弧控制計算次序的問題 比如：( 10 - 4 ) * ( 3 + A ), 實際上計算次序的數目是有限的：
A*(B*(c*D))
A*((B*C)*D)
(A*B)*(C*D)
((A*B)*C)*D
(A*(B*C))*D
2. 需要考慮計算結果為分數的情況：( 3 + (3 / 7) ) * 7
3. 題目中牌的位置可以任意交換
*/
bool TryResolve(char* question, char* answer)
{
int oper[3]; // 存儲運算符，0:加法 1:減法 2:乘法 3:除法
for(int i=0; i<1000 * 1000; i++)
{
// 打亂紙牌順序
shuffle(question);
// 隨機產生運算符
for(int j=0; j<3; j++)
oper[j] = rand() % 4; if( TestResolve(question, oper, answer) ) return true;
} return false;
}
int main(int argc, char* argv[])
{
// 初始化隨機種子
srand( (unsigned)time( NULL ) ); char buf1[4]; // 題目
char buf2[30]; // 解答
printf("***************************\n");
printf("計算24\n");
printf("A J Q K 均按1計算，其它按牌點計算\n");
printf("目標是：通過四則運算組合出結果：24\n");
printf("***************************\n\n");
for(;;)
{
GivePuzzle(buf1); // 出題
printf("題目：");
for(int j=0; j<4; j++){
if( buf1[j] == 'T' )
printf("10 ");
else
printf("%c ", buf1[j]);
} printf("\n按任意鍵參考答案...\n");
getch(); if( TryResolve(buf1, buf2) ) // 解題
printf("參考：%s\n", buf2);
else
printf("可能是無解...\n"); printf("按任意鍵出下一題目，x 鍵退出...\n");
if( getch() == 'x' ) break;
} return 0;
}
❹ 急求c語言小游戲代碼！！！！！
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
#include<windows.h>intboard[10]={2,2,2,2,2,2,2,2,2,2};
intturn=1,flag=0;
intplayer,comp;
voidmenu();
voidgo(intn);
voidstart_game();
voidcheck_draw();
voiddraw_board();//列印棋盤
voidplayer_first();
voidput_X_O(charch,intpos);
//voidgotoxy(int,int);
COORDcoord={0,0};//thisisglobalvariable
//
//*************************************
voidgotoxy(intx,inty)//
{
coord.X=x;
coord.Y=y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE),coord);
}intmain()
{
system("cls");
menu();
getch();
}
//*******************菜單函數*******************
voidmenu()
{
intchoice;
system("cls");
printf(" --------MENU--------");
printf(" 1:PlaywithX");//人先走
printf(" 2:PlaywithO");//電腦先走
printf(" 3:Exit");
printf(" Enteryourchoice:>");
scanf("%d",&choice);
turn=1;
switch(choice)
{
case1:
player=1;
comp=0;
player_first();
break;
case2:
player=0;
comp=1;
start_game();
break;
case3:
exit(1);
default:
menu();
}
}
//*****************************************
intmake2()
{
if(board[5]==2)
return5;
if(board[2]==2)
return2;
if(board[4]==2)
return4;
if(board[6]==2)
return6;
if(board[8]==2)
return8;
return0;
}
intmake4()
{
if(board[1]==2)
return1;
if(board[3]==2)
return3;
if(board[7]==2)
return7;
if(board[9]==2)
return9;
return0;
}
//********************************************
intposswin(intp)
{
//p==1thenXp==0thenO；X為人先開始，O為電腦先開始
inti;
intcheck_val,pos;
if(p==1)
check_val=18;
else
check_val=50;
i=1;
while(i<=9)//rowcheck行檢測
{
if(board[i]*board[i+1]*board[i+2]==check_val)
{
if(board[i]==2)
returni;
if(board[i+1]==2)
returni+1;
if(board[i+2]==2)
returni+2;
}
i+=3;
}
i=1;
while(i<=3)//columncheck列檢測
{
if(board[i]*board[i+3]*board[i+6]==check_val)
{
if(board[i]==2)
returni;
if(board[i+3]==2)
returni+3;
if(board[i+6]==2)
returni+6;
}
i++;
}
if(board[1]*board[5]*board[9]==check_val)//斜對角檢測
{
if(board[1]==2)
return1;
if(board[5]==2)
return5;
if(board[9]==2)
return9;
}
if(board[3]*board[5]*board[7]==check_val)//斜對角檢測
{
if(board[3]==2)
return3;
if(board[5]==2)
return5;
if(board[7]==2)
return7;
}
return0;
}
//************************************
voidgo(intn)
{
if(turn%2)
board[n]=3;
else
board[n]=5;
turn++;
}
//************************************
voidplayer_first()
{
intpos;
check_draw();
draw_board();
gotoxy(30,18);
printf("YourTurn:>");
scanf("%d",&pos);
if(board[pos]!=2)
player_first();
if(pos==posswin(player))
{
go(pos);
draw_board();
gotoxy(30,20);
//textcolor(128+RED);
printf("PlayerWins");
getch();
exit(0);
}
go(pos);
draw_board();
start_game();
}
//**************************************
voidstart_game()
{
//p==1thenXp==0thenO
if(posswin(comp))
{
go(posswin(comp));
flag=1;
}
else
if(posswin(player))
go(posswin(player));
else
if(make2())
go(make2());
else
go(make4());
draw_board();
if(flag)
{
gotoxy(30,20);
//textcolor(128+RED);
printf("Computerwins");
getch();
}
else
player_first();
}
//*********************************
voidcheck_draw()//雙方打平
{
if(turn>9)
{
gotoxy(30,20);
//textcolor(128+RED);
printf("GameDraw");
getch();
exit(0);
}
}
//***************************************
voiddraw_board()
{
intj;
for(j=9;j<17;j++)
{
gotoxy(35,j);
printf("||");
}
gotoxy(28,11);
printf("-----------------------");
gotoxy(28,14);
printf("-----------------------");
for(j=1;j<10;j++)
{
if(board[j]==3)
put_X_O('X',j);
else
if(board[j]==5)
put_X_O('O',j);
}
}
//****************************************
voidput_X_O(charch,intpos)
{
intm;
intx=31,y=10;
m=pos;
if(m>3)
{
while(m>3)
{
y+=3;
m-=3;
}
}
if(pos%3==0)
x+=16;
else
{
pos%=3;
pos--;
while(pos)
{
x+=8;
pos--;
}
}
gotoxy(x,y);
printf("%c",ch);
}
xo棋
❺ 求一個用C語言編寫的小游戲代碼
#include <graphics.h>
#include <conio.h>
#include <time.h>
/////////////////////////////////////////////
// 定義常量、枚舉量、結構體、全局變數
/////////////////////////////////////////////
#define WIDTH 10 // 游戲區寬度
#define HEIGHT 22 // 游戲區高度
#define SIZE 20 // 每個游戲區單位的實際像素
// 定義操作類型
enum CMD
{
CMD_ROTATE, // 方塊旋轉
CMD_LEFT, CMD_RIGHT, CMD_DOWN, // 方塊左、右、下移動
CMD_SINK, // 方塊沉底
CMD_QUIT // 退出遊戲
};
// 定義繪制方塊的方法
enum DRAW
{
SHOW, // 顯示方塊
HIDE, // 隱藏方塊
FIX // 固定方塊
};
// 定義七種俄羅斯方塊
struct BLOCK
{
WORD dir[4]; // 方塊的四個旋轉狀態
COLORREF color; // 方塊的顏色
} g_Blocks[7] = { {0x0F00, 0x4444, 0x0F00, 0x4444, RED}, // I
{0x0660, 0x0660, 0x0660, 0x0660, BLUE}, // 口
{0x4460, 0x02E0, 0x0622, 0x0740, MAGENTA}, // L
{0x2260, 0x0E20, 0x0644, 0x0470, YELLOW}, // 反L
{0x0C60, 0x2640, 0x0C60, 0x2640, CYAN}, // Z
{0x0360, 0x4620, 0x0360, 0x4620, GREEN}, // 反Z
{0x4E00, 0x4C40, 0x0E40, 0x4640, BROWN}}; // T
// 定義當前方塊、下一個方塊的信息
struct BLOCKINFO
{
byte id; // 方塊 ID
char x, y; // 方塊在游戲區中的坐標
byte dir:2; // 方向
} g_CurBlock, g_NextBlock;
// 定義游戲區
BYTE g_World[WIDTH][HEIGHT] = {0};
/////////////////////////////////////////////
// 函數聲明
/////////////////////////////////////////////
void Init(); // 初始化游戲
void Quit(); // 退出遊戲
void NewGame(); // 開始新游戲
void GameOver(); // 結束游戲
CMD GetCmd(); // 獲取控制命令
void DispatchCmd(CMD _cmd); // 分發控制命令
void NewBlock(); // 生成新的方塊
bool CheckBlock(BLOCKINFO _block); // 檢測指定方塊是否可以放下
void DrawBlock(BLOCKINFO _block, DRAW _draw = SHOW); // 畫方塊
void OnRotate(); // 旋轉方塊
void OnLeft(); // 左移方塊
void OnRight(); // 右移方塊
void OnDown(); // 下移方塊
void OnSink(); // 沉底方塊
/////////////////////////////////////////////
// 函數定義
/////////////////////////////////////////////
// 主函數
void main()
{
Init();
CMD c;
while(true)
{
c = GetCmd();
DispatchCmd(c);
// 按退出時，顯示對話框咨詢用戶是否退出
if (c == CMD_QUIT)
{
HWND wnd = GetHWnd();
if (MessageBox(wnd, _T("您要退出遊戲嗎？"), _T("提醒"), MB_OKCANCEL | MB_ICONQUESTION) == IDOK)
Quit();
}
}
}
// 初始化游戲
void Init()
{
initgraph(640, 480);
srand((unsigned)time(NULL));
// 顯示操作說明
setfont(14, 0, _T("宋體"));
outtextxy(20, 330, _T("操作說明"));
outtextxy(20, 350, _T("上：旋轉"));
outtextxy(20, 370, _T("左：左移"));
outtextxy(20, 390, _T("右：右移"));
outtextxy(20, 410, _T("下：下移"));
outtextxy(20, 430, _T("空格：沉底"));
outtextxy(20, 450, _T("ESC：退出"));
// 設置坐標原點
setorigin(220, 20);
// 繪制游戲區邊界
rectangle(-1, -1, WIDTH * SIZE, HEIGHT * SIZE);
rectangle((WIDTH + 1) * SIZE - 1, -1, (WIDTH + 5) * SIZE, 4 * SIZE);
// 開始新游戲
NewGame();
}
// 退出遊戲
void Quit()
{
closegraph();
exit(0);
}
// 開始新游戲
void NewGame()
{
// 清空游戲區
setfillstyle(BLACK);
bar(0, 0, WIDTH * SIZE - 1, HEIGHT * SIZE - 1);
ZeroMemory(g_World, WIDTH * HEIGHT);
// 生成下一個方塊
g_NextBlock.id = rand() % 7;
g_NextBlock.dir = rand() % 4;
g_NextBlock.x = WIDTH + 1;
g_NextBlock.y = HEIGHT - 1;
// 獲取新方塊
NewBlock();
}
// 結束游戲
void GameOver()
{
HWND wnd = GetHWnd();
if (MessageBox(wnd, _T("游戲結束。\n您想重新來一局嗎？"), _T("游戲結束"), MB_YESNO | MB_ICONQUESTION) == IDYES)
NewGame();
else
Quit();
}
// 獲取控制命令
DWORD m_oldtime;
CMD GetCmd()
{
// 獲取控制值
while(true)
{
// 如果超時，自動下落一格
DWORD newtime = GetTickCount();
if (newtime - m_oldtime >= 500)
{
m_oldtime = newtime;
return CMD_DOWN;
}
// 如果有按鍵，返回按鍵對應的功能
if (kbhit())
{
switch(getch())
{
case 'w':
case 'W': return CMD_ROTATE;
case 'a':
case 'A': return CMD_LEFT;
case 'd':
case 'D': return CMD_RIGHT;
case 's':
case 'S': return CMD_DOWN;
case 27: return CMD_QUIT;
case ' ': return CMD_SINK;
case 0:
case 0xE0:
switch(getch())
{
case 72: return CMD_ROTATE;
case 75: return CMD_LEFT;
case 77: return CMD_RIGHT;
case 80: return CMD_DOWN;
}
}
}
// 延時 (降低 CPU 佔用率)
Sleep(20);
}
}
// 分發控制命令
void DispatchCmd(CMD _cmd)
{
switch(_cmd)
{
case CMD_ROTATE: OnRotate(); break;
case CMD_LEFT: OnLeft(); break;
case CMD_RIGHT: OnRight(); break;
case CMD_DOWN: OnDown(); break;
case CMD_SINK: OnSink(); break;
case CMD_QUIT: break;
}
}
// 生成新的方塊
void NewBlock()
{
g_CurBlock.id = g_NextBlock.id, g_NextBlock.id = rand() % 7;
g_CurBlock.dir = g_NextBlock.dir, g_NextBlock.dir = rand() % 4;
g_CurBlock.x = (WIDTH - 4) / 2;
g_CurBlock.y = HEIGHT + 2;
// 下移新方塊直到有局部顯示
WORD c = g_Blocks[g_CurBlock.id].dir[g_CurBlock.dir];
while((c & 0xF) == 0)
{
g_CurBlock.y--;
c >>= 4;
}
// 繪制新方塊
DrawBlock(g_CurBlock);
// 繪制下一個方塊
setfillstyle(BLACK);
bar((WIDTH + 1) * SIZE, 0, (WIDTH + 5) * SIZE - 1, 4 * SIZE - 1);
DrawBlock(g_NextBlock);
// 設置計時器，用於判斷自動下落
m_oldtime = GetTickCount();
}
// 畫方塊
void DrawBlock(BLOCKINFO _block, DRAW _draw)
{
WORD b = g_Blocks[_block.id].dir[_block.dir];
int x, y;
int color = BLACK;
switch(_draw)
{
case SHOW: color = g_Blocks[_block.id].color; break;
case HIDE: color = BLACK; break;
case FIX: color = g_Blocks[_block.id].color / 3; break;
}
setfillstyle(color);
for(int i=0; i<16; i++)
{
if (b & 0x8000)
{
x = _block.x + i % 4;
y = _block.y - i / 4;
if (y < HEIGHT)
{
if (_draw != HIDE)
bar3d(x * SIZE + 2, (HEIGHT - y - 1) * SIZE + 2, (x + 1) * SIZE - 4, (HEIGHT - y) * SIZE - 4, 3, true);
else
bar(x * SIZE, (HEIGHT - y - 1) * SIZE, (x + 1) * SIZE - 1, (HEIGHT - y) * SIZE - 1);
}
}
b <<= 1;
}
}
// 檢測指定方塊是否可以放下
bool CheckBlock(BLOCKINFO _block)
{
WORD b = g_Blocks[_block.id].dir[_block.dir];
int x, y;
for(int i=0; i<16; i++)
{
if (b & 0x8000)
{
x = _block.x + i % 4;
y = _block.y - i / 4;
if ((x < 0) || (x >= WIDTH) || (y < 0))
return false;
if ((y < HEIGHT) && (g_World[x][y]))
return false;
}
b <<= 1;
}
return true;
}
// 旋轉方塊
void OnRotate()
{
// 獲取可以旋轉的 x 偏移量
int dx;
BLOCKINFO tmp = g_CurBlock;
tmp.dir++; if (CheckBlock(tmp)) { dx = 0; goto rotate; }
tmp.x = g_CurBlock.x - 1; if (CheckBlock(tmp)) { dx = -1; goto rotate; }
tmp.x = g_CurBlock.x + 1; if (CheckBlock(tmp)) { dx = 1; goto rotate; }
tmp.x = g_CurBlock.x - 2; if (CheckBlock(tmp)) { dx = -2; goto rotate; }
tmp.x = g_CurBlock.x + 2; if (CheckBlock(tmp)) { dx = 2; goto rotate; }
return;
rotate:
// 旋轉
DrawBlock(g_CurBlock, HIDE);
g_CurBlock.dir++;
g_CurBlock.x += dx;
DrawBlock(g_CurBlock);
}
// 左移方塊
void OnLeft()
{
BLOCKINFO tmp = g_CurBlock;
tmp.x--;
if (CheckBlock(tmp))
{
DrawBlock(g_CurBlock, HIDE);
g_CurBlock.x--;
DrawBlock(g_CurBlock);
}
}
// 右移方塊
void OnRight()
{
BLOCKINFO tmp = g_CurBlock;
tmp.x++;
if (CheckBlock(tmp))
{
DrawBlock(g_CurBlock, HIDE);
g_CurBlock.x++;
DrawBlock(g_CurBlock);
}
}
// 下移方塊
void OnDown()
{
BLOCKINFO tmp = g_CurBlock;
tmp.y--;
if (CheckBlock(tmp))
{
DrawBlock(g_CurBlock, HIDE);
g_CurBlock.y--;
DrawBlock(g_CurBlock);
}
else
OnSink(); // 不可下移時，執行「沉底方塊」操作
}
// 沉底方塊
void OnSink()
{
int i, x, y;
// 連續下移方塊
DrawBlock(g_CurBlock, HIDE);
BLOCKINFO tmp = g_CurBlock;
tmp.y--;
while (CheckBlock(tmp))
{
g_CurBlock.y--;
tmp.y--;
}
DrawBlock(g_CurBlock, FIX);
// 固定方塊在游戲區
WORD b = g_Blocks[g_CurBlock.id].dir[g_CurBlock.dir];
for(i = 0; i < 16; i++)
{
if (b & 0x8000)
{
if (g_CurBlock.y - i / 4 >= HEIGHT)
{ // 如果方塊的固定位置超出高度，結束游戲
GameOver();
return;
}
else
g_World[g_CurBlock.x + i % 4][g_CurBlock.y - i / 4] = 1;
}
b <<= 1;
}
// 檢查是否需要消掉行，並標記
int row[4] = {0};
bool bRow = false;
for(y = g_CurBlock.y; y >= max(g_CurBlock.y - 3, 0); y--)
{
i = 0;
for(x = 0; x < WIDTH; x++)
if (g_World[x][y] == 1)
i++;
if (i == WIDTH)
{
bRow = true;
row[g_CurBlock.y - y] = 1;
setfillstyle(WHITE, DIAGCROSS2_FILL);
bar(0, (HEIGHT - y - 1) * SIZE + SIZE / 2 - 2, WIDTH * SIZE - 1, (HEIGHT - y - 1) * SIZE + SIZE / 2 + 2);
}
}
if (bRow)
{
// 延時 200 毫秒
Sleep(200);
// 擦掉剛才標記的行
IMAGE img;
for(i = 0; i < 4; i++)
{
if (row[i])
{
for(y = g_CurBlock.y - i + 1; y < HEIGHT; y++)
for(x = 0; x < WIDTH; x++)
{
g_World[x][y - 1] = g_World[x][y];
g_World[x][y] = 0;
}
getimage(&img, 0, 0, WIDTH * SIZE, (HEIGHT - (g_CurBlock.y - i + 1)) * SIZE);
putimage(0, SIZE, &img);
}
}
}
// 產生新方塊
NewBlock();
}
❻ 用C語言編寫的小游戲代碼是什麼
"掃雷"小游戲C代碼
#include<stdio.h>
#include<math.h>
#include<time.h>
#include<stdlib.h>
main( )
{char a[102][102],b[102][102],c[102][102],w;
int i,j; /*循環變數*/
int x,y,z[999]; /*雷的位置*/
int t,s; /*標記*/
int m,n,lei; /*計數*/
int u,v; /*輸入*/
int hang,lie,ge,mo; /*自定義變數*/
srand((int)time(NULL)); /*啟動隨機數發生器*/
leb1: /*選擇模式*/
printf("
請選擇模式：
1.標准 2.自定義
");
scanf("%d",&mo);
if(mo==2) /*若選擇自定義模式，要輸入三個參數*/
{do
{t=0; printf("請輸入
行數 列數 雷的個數
");
scanf("%d%d%d",&hang,&lie,&ge);
if(hang<2){printf("行數太少
"); t=1;}
if(hang>100){printf("行數太多
");t=1;}
if(lie<2){printf("列數太少
");t=1;}
if(lie>100){printf("列數太多
");t=1;}
if(ge<1){printf("至少要有一個雷
");t=1;}
if(ge>=(hang*lie)){printf("雷太多了
");t=1;}
}while(t==1);
}
else{hang=10,lie=10,ge=10;} /*否則就是選擇了標准模式(默認參數)*/
for(i=1;i<=ge;i=i+1) /*確定雷的位置*/
{do
{t=0; z[i]=rand( )%(hang*lie);
for(j=1;j<i;j=j+1){if(z[i]==z[j]) t=1;}
}while(t==1);
}
for(i=0;i<=hang+1;i=i+1) /*初始化a,b,c*/
{for(j=0;j<=lie+1;j=j+1) {a[i][j]='1'; b[i][j]='1'; c[i][j]='0';} }
for(i=1;i<=hang;i=i+1)
{for(j=1;j<=lie;j=j+1) {a[i][j]='+';} }
for(i=1;i<=ge;i=i+1) /*把雷放入c*/
{x=z[i]/lie+1; y=z[i]%lie+1; c[x][y]='#';}
for(i=1;i<=hang;i=i+1) /*計算b中數字*/
{for(j=1;j<=lie;j=j+1)
{m=48;
if(c[i-1][j-1]=='#')m=m+1; if(c[i][j-1]=='#')m=m+1;
if(c[i-1][j]=='#')m=m+1; if(c[i+1][j+1]=='#')m=m+1;
if(c[i][j+1]=='#')m=m+1; if(c[i+1][j]=='#')m=m+1;
if(c[i+1][j-1]=='#')m=m+1; if(c[i-1][j+1]=='#')m=m+1;
b[i][j]=m;
}
}
for(i=1;i<=ge;i=i+1) /*把雷放入b中*/
{x=z[i]/lie+1; y=z[i]%lie+1; b[x][y]='#';}
lei=ge; /*以下是游戲設計*/
do
{leb2: /*輸出*/
system("cls");printf("
");
printf(" ");
for(i=1;i<=lie;i=i+1)
{w=(i-1)/10+48; printf("%c",w);
w=(i-1)%10+48; printf("%c ",w);
}
printf("
|");
for(i=1;i<=lie;i=i+1){printf("---|");}
printf("
");
for(i=1;i<=hang;i=i+1)
{w=(i-1)/10+48; printf("%c",w);
w=(i-1)%10+48; printf("%c |",w);
for(j=1;j<=lie;j=j+1)
{if(a[i][j]=='0')printf(" |");
else printf(" %c |",a[i][j]);
}
if(i==2)printf(" 剩餘雷個數");
if(i==3)printf(" %d",lei);
printf("
|");
for(j=1;j<=lie;j=j+1){printf("---|");}
printf("
");
}
scanf("%d%c%d",&u,&w,&v); /*輸入*/
u=u+1,v=v+1;
if(w!='#'&&a[u][v]=='@')
goto leb2;
if(w=='#')
{if(a[u][v]=='+'){a[u][v]='@'; lei=lei-1;}
else if(a[u][v]=='@'){a[u][v]='?'; lei=lei+1;}
else if(a[u][v]=='?'){a[u][v]='+';}
goto leb2;
}
a[u][v]=b[u][v];
leb3: /*打開0區*/
t=0;
if(a[u][v]=='0')
{for(i=1;i<=hang;i=i+1)
{for(j=1;j<=lie;j=j+1)
{s=0;
if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;
if(a[i-1][j]=='0')s=1; if(a[i+1][j-1]=='0')s=1;
if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;
if(a[i][j-1]=='0')s=1; if(a[i][j+1]=='0')s=1;
if(s==1)a[i][j]=b[i][j];
}
}
for(i=1;i<=hang;i=i+1)
{for(j=lie;j>=1;j=j-1)
{s=0;
if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;
if(a[i-1][j]=='0')s=1; if(a[i+1][j-1]=='0')s=1;
if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;
if(a[i][j-1]=='0')s=1; if(a[i][j+1]=='0')s=1;
if(s==1)a[i][j]=b[i][j];
}
}
for(i=hang;i>=1;i=i-1)
{for(j=1;j<=lie;j=j+1)
{s=0;
if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;
if(a[i-1][j]=='0')s=1; if(a[i+1][j-1]=='0')s=1;
if(a[i+1][j+1]=='0')s=1; if(a[i+1][j]=='0')s=1;
if(a[i][j-1]=='0')s=1; if(a[i][j+1]=='0')s=1;
if(s==1)a[i][j]=b[i][j];
}
}
for(i=hang;i>=1;i=i-1)
{for(j=lie;j>=1;j=j-1)
{s=0;
if(a[i-1][j-1]=='0')s=1; if(a[i-1][j+1]=='0')s=1;
if(a[i-1][j]=='0')s=1; if(a[i+1][j-1]=='0')s=1;
if(a[i+1][j+1]=='0')s=1;if(a[i+1][j]=='0')s=1;
if(a[i][j-1]=='0')s=1; if(a[i][j+1]=='0')s=1;
if(s==1)a[i][j]=b[i][j];
}
}
for(i=1;i<=hang;i=i+1) /*檢測0區*/
{for(j=1;j<=lie;j=j+1)
{if(a[i][j]=='0')
{if(a[i-1][j-1]=='+'||a[i-1][j-1]=='@'||a[i-1][j-1]=='?')t=1;
if(a[i-1][j+1]=='+'||a[i-1][j+1]=='@'||a[i-1][j+1]=='?')t=1;
if(a[i+1][j-1]=='+'||a[i+1][j-1]=='@'||a[i+1][j-1]=='?')t=1;
if(a[i+1][j+1]=='+'||a[i+1][j+1]=='@'||a[i+1][j+1]=='?')t=1;
if(a[i+1][j]=='+'||a[i+1][j]=='@'||a[i+1][j]=='?')t=1;
if(a[i][j+1]=='+'||a[i][j+1]=='@'||a[i][j+1]=='?')t=1;
if(a[i][j-1]=='+'||a[i][j-1]=='@'||a[i][j-1]=='?')t=1;
if(a[i-1][j]=='+'||a[i-1][j]=='@'||a[i-1][j]=='?')t=1;
}
}
}
if(t==1)goto leb3;
}
n=0; /*檢查結束*/
for(i=1;i<=hang;i=i+1)
{for(j=1;j<=lie;j=j+1)
{if(a[i][j]!='+'&&a[i][j]!='@'&&a[i][j]!='?')n=n+1;}
}
}
while(a[u][v]!='#'&&n!=(hang*lie-ge));
for(i=1;i<=ge;i=i+1) /*游戲結束*/
{x=z[i]/lie+1; y=z[i]%lie+1; a[x][y]='#'; }
printf(" ");
for(i=1;i<=lie;i=i+1)
{w=(i-1)/10+48; printf("%c",w);
w=(i-1)%10+48; printf("%c ",w);
}
printf("
|");
for(i=1;i<=lie;i=i+1){printf("---|");}
printf("
");
for(i=1;i<=hang;i=i+1)
{w=(i-1)/10+48; printf("%c",w);
w=(i-1)%10+48; printf("%c |",w);
for(j=1;j<=lie;j=j+1)
{if(a[i][j]=='0')printf(" |");
else printf(" %c |",a[i][j]);
}
if(i==2)printf(" 剩餘雷個數");
if(i==3)printf(" %d",lei); printf("
|");
for(j=1;j<=lie;j=j+1) {printf("---|");}
printf("
");
}
if(n==(hang*lie-ge)) printf("你成功了!
");
else printf(" 游戲結束!
");
printf(" 重玩請輸入1
");
t=0;
scanf("%d",&t);
if(t==1)goto leb1;
}
/*註：在DEV c++上運行通過。行號和列號都從0開始，比如要確定第0行第9列不是「雷」，就在0和9中間加入一個字母，可以輸入【0a9】三個字元再按回車鍵。3行7列不是雷，則輸入【3a7】回車；第8行第5列是雷，就輸入【8#5】回車，9行0列是雷則輸入【9#0】並回車*/
❼ 求一些C語言小游戲的源代碼，謝謝
「推箱子」C代碼：
#include <stdio.h>
#include <conio.h>
#include<stdlib.h>
#include<windows.h>
int m =0; //m代表第幾關
struct maps{short a[9][11]; };
struct maps map[5]={ 0,0,0,0,0,0,0,0,0,0,0, //共5關,每關9行11列
0,1,1,1,1,1,1,1,0,0,0,
0,1,0,0,0,0,0,1,1,1,0,
1,1,4,1,1,1,0,0,0,1,0, //0空地,1牆
1,5,0,0,4,0,0,4,0,1,0, //4是箱子,5是人
1,0,3,3,1,0,4,0,1,1,0, //3是目的地
1,1,3,3,1,0,0,0,1,0,0, //7是箱子在目的地(4+3)
0,1,1,1,1,1,1,1,1,0,0, //8是人在目的地(5+3)
0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,
0,0,1,1,1,1,0,0,0,0,0,
0,0,1,5,0,1,1,1,0,0,0,
0,0,1,0,4,0,0,1,0,0,0,
0,1,1,1,0,1,0,1,1,0,0,
0,1,3,1,0,1,0,0,1,0,0,
0,1,3,4,0,0,1,0,1,0,0,
0,1,3,0,0,0,4,0,1,0,0,
0,1,1,1,1,1,1,1,1,0,0,
0,0,0,0,0,0,0,0,0,0,0,
0,0,0,1,1,1,1,1,1,1,0,
0,0,1,1,0,0,1,0,5,1,0,
0,0,1,0,0,0,1,0,0,1,0,
0,0,1,4,0,4,0,4,0,1,0,
0,0,1,0,4,1,1,0,0,1,0,
1,1,1,0,4,0,1,0,1,1,0,
1,3,3,3,3,3,0,0,1,0,0,
1,1,1,1,1,1,1,1,1,0,0,
0,1,1,1,1,1,1,1,1,1,0,
0,1,0,0,1,1,0,0,0,1,0,
0,1,0,0,0,4,0,0,0,1,0,
0,1,4,0,1,1,1,0,4,1,0,
0,1,0,1,3,3,3,1,0,1,0,
1,1,0,1,3,3,3,1,0,1,1,
1,0,4,0,0,4,0,0,4,0,1,
1,0,0,0,0,0,1,0,5,0,1,
1,1,1,1,1,1,1,1,1,1,1,
0,0,0,0,0,0,0,0,0,0,0,
0,0,0,1,1,1,1,1,1,0,0,
0,1,1,1,0,0,0,0,1,0,0,
1,1,3,0,4,1,1,0,1,1,0,
1,3,3,4,0,4,0,0,5,1,0,
1,3,3,0,4,0,4,0,1,1,0,
1,1,1,1,1,1,0,0,1,0,0,
0,0,0,0,0,1,1,1,1,0,0,
0,0,0,0,0,0,0,0,0,0,0 };
void DrMap( ) //繪制地圖
{ CONSOLE_CURSOR_INFO cursor_info={1,0}; //隱藏游標的設置
SetConsoleCursorInfo(GetStdHandle(STD_OUTPUT_HANDLE),&cursor_info);
printf(" 推箱子");
printf(" ");
for (int i = 0; i < 9; i++)
{for (int j = 0; j < 11; j++)
{switch (map[m].a[i][j])
{case 0: printf(" "); break;
case 1: printf("■"); break;
case 3: printf("◎");break;
case 4: printf("□"); break;
case 5: printf("♀"); break; //5是人
case 7: printf("□"); break; //4 + 3箱子在目的地中
case 8: printf("♀");break; // 5 + 3人在目的地中
}
}
printf(" ");
}
}
void gtxy(int x, int y) //控制游標位置的函數
{ COORD coord;
coord.X = x;
coord.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
}
void start( ) //開始游戲
{ int r, c; //人的下標
for (int i = 0; i < 9; i++)
{ for (int j = 0; j < 11; j++)
{if (map[m].a[i][j] == 5||map[m].a[i][j]==8) { r = i; c = j; } } //i j 人的下標
}
char key;
key = getch( );
switch (key)
{case 'W':
case 'w':
case 72:
if (map[m]. a[r - 1][c] == 0|| map[m]. a [r - 1][c] == 3)
{ gtxy(2*c+8,r-1+3); printf("♀"); // gtxy(2*c+8,r-1+3)是到指定位置輸出字元
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r - 1][c] += 5; map[m]. a [r][c] -= 5; }
else if (map[m]. a [r - 1][c] == 4 || map[m]. a [r - 1][c] == 7)
{ if (map[m]. a [r - 2][c] == 0 || map[m]. a [r - 2][c] == 3)
{ gtxy(2*c+8,r-2+3); printf("□"); gtxy(2*c+8,r-1+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r - 2][c] += 4; map[m]. a [r - 1][c] += 1;
map[m]. a [r][c] -= 5; }
} break;
case 'S':
case 's':
case 80:
if (map[m]. a [r + 1][c] == 0 || map[m]. a [r + 1][c] == 3)
{ gtxy(2*c+8,r+1+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r + 1][c] += 5; map[m]. a [r][c] -= 5; }
else if (map[m]. a [r + 1][c] == 4 || map[m]. a [r+ 1][c] == 7)
{ if (map[m]. a [r + 2][c] == 0 || map[m]. a [r + 2][c] == 3)
{ gtxy(2*c+8,r+2+3); printf("□"); gtxy(2*c+8,r+1+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r + 2][c] += 4; map[m]. a [r + 1][c] += 1;
map[m]. a [r][c] -= 5; }
}break;
case 'A':
case 'a':
case 75:
if (map[m]. a [r ][c - 1] == 0 || map[m]. a [r ][c - 1] == 3)
{ gtxy(2*(c-1)+8,r+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r ][c - 1] += 5; map[m]. a [r][c] -= 5; }
else if (map[m]. a [r][c - 1] == 4 || map[m]. a [r][c - 1] == 7)
{if (map[m]. a [r ][c - 2] == 0 || map[m]. a [r ][c - 2] == 3)
{ gtxy(2*(c-2)+8,r+3); printf("□"); gtxy(2*(c-1)+8,r+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r ][c - 2] += 4; map[m]. a [r ][c - 1] += 1;
map[m]. a [r][c] -= 5; }
}break;
case 'D':
case 'd':
case 77:
if (map[m]. a [r][c + 1] == 0 || map[m]. a [r][c + 1] == 3)
{ gtxy(2*(c+1)+8,r+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8) {gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r][c + 1] += 5; map[m]. a [r][c] -= 5; }
else if (map[m]. a [r][c + 1] == 4 || map[m]. a [r][c + 1] == 7)
{ if (map[m]. a [r][c + 2] == 0 || map[m]. a [r][c + 2] == 3)
{ gtxy(2*(c+2)+8,r+3); printf("□"); gtxy(2*(c+1)+8,r+3); printf("♀");
if(map[m]. a[r ][c] == 5){gtxy(2*c+8,r+3); printf(" "); }
if(map[m]. a[r ][c] == 8){gtxy(2*c+8,r+3); printf("◎");}
map[m]. a [r][c + 2] += 4; map[m]. a [r][c + 1] += 1;
map[m]. a [r][c] -= 5; }
}break;
}
}
int ifwan( ) //是否完成(1是0否)
{ if(m==0){if(map[m].a[5][2]==7&& map[m].a[5][3]==7&&
map[m].a[6][2]==7&& map[m].a[6][3]==7) return 1;}
if(m==1){if(map[m].a[5][2]==7&& map[m].a[6][2]==7&&
map[m].a[7][2]==7) return 1;}
if(m==2){if(map[m].a[7][1]==7&& map[m].a[7][2]==7&& map[m].a[7][3]==7&&
map[m].a[7][4]==7&& map[m].a[7][5]==7) return 1;}
if(m==3){if(map[m].a[4][4]==7&& map[m].a[4][5]==7&& map[m].a[4][6]==7&&
map[m].a[5][4]==7&& map[m].a[5][5]==7&& map[m].a[5][6]==7) return 1;}
if(m==4){if(map[m].a[3][2]==7&& map[m].a[4][1]==7&& map[m].a[4][2]==7&&
map[m].a[5][1]==7&& map[m].a[5][2]==7) return 1;}
return 0;
}
int main( ) //主函數
{ while (1)
{ system("cls");
DrMap( );
while (1)
{ start( );
if(ifwan()){printf(" 07");break;} //完成後響鈴
}
m+=1;
}
return 0;
}